Y varies inversely as the square of x. If y=10 and x=4, find x if y=8

Answer:

[tex]2xy^2(xy-1)(xy-3)[/tex]

====================

Given expression

[tex]2x^3y^4-8x^2y^3+6xy^2[/tex]

The greatest common factor of all three terms is [tex]2xy^2[/tex].

Factor this out:

[tex]2xy^2(x^2y^2-4xy+3)[/tex]

Complete the square:

[tex]2xy^2(x^2y^2-4xy+4-1)=[/tex]

[tex]2xy^2((xy-2)^2-1)[/tex]

Factorize further using the identity for the difference of squares:

[tex]2xy^2(xy-2+1)(xy-2-1)=[/tex]

[tex]2xy^2(xy-1)(xy-3)[/tex]

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \: scale \: \: factor = \cfrac{new \: \: measure}{original \: measure} [/tex]

[tex]\qquad \sf  \dashrightarrow \: s = \dfrac{6}{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: s = 3[/tex]

so, correct choice is D

[tex]\cos \left(\frac{3\pi}{2}-x \right)=\sin x \\ \\ =\cos \left(\frac{3\pi}{2} \right)\cos x -\sin \left(\frac{3\pi}{2} \right) \sin x \\ \\ =0\cos x -(-1)(\sin x) \\ \\ =\sin x[/tex]

The amount of money Craig paid more than Tim if the shop has an offer of reduction if a particular amount is spent is £88.

The shop discount:

£5 reduction if you spend more than £100

or

£10 reduction if you spend more than £140

or

£20 reduction if you spend more than £180

Cost of a shirt = £49

Tim buys 3 shirts

Total cost of Tim's shirt = £49 × 3

= £147

Amount Tim paid = £147 - £10

= £137

Craig buys 5 shirts

Total cost of Craig's shirt = £49 × 5

= £245

Amount Craig paid = £245 - £20

= £225

Difference between Tim and Craig's pay = £225 - £137

= £88

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The drivers will travel 200x miles during the race.

A definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

Given that A race track is miles long

The car race is 200 laps then we have to find the number of miles the driver travel.

If the race track is x miles long, then one lap around the track is x miles.

If the race is 200 laps, the total distance covered by the drivers is:

200 laps ×  x miles/lap = 200x miles.

Therefore, the drivers will travel 200x miles during the race.

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Answer:

2

Step-by-step explanation:

8/3 = 2 with a Remainder of 2

The number of solutions there are for the functions, -f(x) and f(-x) are; 2 and 2 respectively.

According to the task content, the function given initially is; f(x).

Hence, the function -f(x) represents a reflection of the function f(x) over the x axis. And in this case scenario, the reflection also has 2 solutions as it only cuts the x-axis at two points.

Also, the function f(-x) represents a reflection of the function f(x) over the y-axis. And in this case scenario, the reflection also has 2 solutions as it only cuts the x-axis at two points.

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The attached figure represents the image of A"B"C" after the transformation

The transformation rule is given as:

A"B"C" = Ro90° (T(-4,3)(ABC))

This means that we rotate the triangle 90 degrees clockwise, and then translate the triangle

From the figure, the coordinates of ABC are

A = (-1, 2)

B = (1, 4)

C = (3, -1)

The rule of 90 degrees clockwise rotation is

(x,y) ⇒ (y,-x)

So, we have

A' = (2, 1)

B' = (4, -1)

C' = (-1, -3)

The translation of the triangle by T(-4,3) is

(x,y) ⇒ (x - 4, y + 3)

So, we have

A'' = (-2, 4)

B'' = (0, 2)

C'' = (-5, 0)

See attachment for the image of the transformation

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Answer:

8.1

Step-by-step explanation:

[tex]\sqrt{(-1-0)^2 + (5-(-3))^2}=\sqrt{65} \approx 8.1[/tex]

The simplified expression of [tex]\frac{x^{3}-8x^{2}}{x^2-64}[/tex] is [tex]\frac{x^2}{x + 8}[/tex]

The expression is given as:

[tex]\frac{x^{3}-8x^{2}}{x^2-64}[/tex]

Factor the numerator

[tex]\frac{x^{2}(x-8)}{x^2-64}[/tex]

Express the denominator as a difference of two squares

[tex]\frac{x^{2}(x-8)}{(x-8)(x + 8)}[/tex]

Cancel out the common factor

[tex]\frac{x^2}{x + 8}[/tex]

Hence, the simplified expression of [tex]\frac{x^{3}-8x^{2}}{x^2-64}[/tex] is [tex]\frac{x^2}{x + 8}[/tex]

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The probability of a meerkat living smaller than 16.1 years exists at 99.85%.

The empirical rule notes that for a normal distribution most of the data lose within three standard deviations (σ) of the mean (µ). That exists 68% of the data lose within the first standard deviation (µ ± σ), 95% loses within the first two standard deviations (µ ± 2σ), and 99.7% declines within the first three standard deviations (µ ± 3σ).

68% declines within (10.4 ± 1.9). 68% declines within 8.5 years to 12.3 years.

95% declines within (10.4 ± 2[tex]*[/tex]1.9). 95% declines within 6.6 years to 14.2 years.

99.7% declines within (10.4 ± 3 [tex]*[/tex]1.9). 68% declines within 4.7 years to 16.1 years.

Probability of a meerkat living less than 16.1 years

= 100% - (100% - 99.7%)/2

= 100% - 0.15%

= 99.85%

Therefore, the probability of a meerkat living less than 16.1 years exists at 99.85%.

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Answer:

[tex]\fbox {Required equation : 4(x + 3) = 20}[/tex]

[tex]\fbox {Result : x = 2}[/tex]

Step-by-step explanation:

Let our number be x.

1) 3 is added to this number.

2) It is multiplied by 4.

3) It is equated to 20.

∴ This is our framed equation.

Steps to solve :

1) Divide by 4 on both sides.

2) Subtract 3 on both sides.

∴ The number is 2.

From the line theorems explained below and when we apply it to the given image, we have; X║Y, A║B, Z ⊥ A

The perpendicular transversal theorem states that in a plane, if a line is perpendicular to one of two parallel lines, then it is also perpendicular to the other line.

Now, since we are told that Line X is perpendicular to Line A, then it means that Line X is also perpendicular to line B.

The inverse of perpendicular transversal theorem states that if there are two perpendicular lines to a straight line, they're parallel to each other. Thus, it means that Line X is parallel to Line Y and similarly, line A is parallel to Line B.

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The probability of drawing a red marble and then a green marble is:

P = 1/6.

In the jar we have a total of 16 marbles, such that:

First, the probability of getting a red marble is give by the quotient between the number of red marbles and the total number of marbles:

p = 4/16 = 1/4

Now we need to draw a green one, the probability is computed in the same way, but this time there are 15 marbles, because we already took one.

q = 10/15

The joint probability (first drawing red, then green) is given by the product between the individual probabilities:

P = p*q = (1/4)*(10/15) = 10/60 = 1/6

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Thermal energy can be used in the heating systems either at home or in the industries

However, when solar energy is converted to thermal energy, the radiant energy from the sunlight is converted into heat which can then be used as space and hot water heating, power generation and industrial process heat

Energy simply refers to the capacity of doing work. Some forms of energy are:

So therefore, thermal energy can be used in the heating systems either at home or in the industries.

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Answer:

b) - 10

Step-by-step explanation:

To find the average rate of change, we have divide the change in y of f(x) , by the change in x(input).

   [tex]\sf \boxed{\text{\bf Average rate of change = $\dfrac{f(b)-f(a)}{b-a}$}}[/tex]

 a = 4 ; f(a) = -17

b = 6 ;   f(b) = -37

     [tex]\sf Average \ rate \ of \ change = \dfrac{-37-[-17]}{6-4}[/tex]

                                         [tex]\sf =\dfrac{-37+17}{2}\\\\=\dfrac{-20}{2}\\\\=-10[/tex]

Answer:

0.2

Step-by-step explanation:

y = mx + b  The slope is the number before the x.

Use the slope-intercept form to estimate the slope and y-intercept.

Slope: 0.2

y-intercept: (0,−6.9)

The slope intercept form in math exists as one of the forms utilized to estimate the equation of a straight line, given the slope of the line and intercept it forms with the y-axis.

The slope-intercept form exists y = mx + b, where m exists the slope and b exists the y-intercept.

y = mx + b

Use the slope-intercept form to estimate the slope and y-intercept.

Slope: 0.2

y-intercept: (0,−6.9)

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The resulting coordinates for each row are (-2, 2), (0, 4),()2, 6), (6, 10) and (8,12) respectively

Given the linear function expressed as;

y = x + 4

where

x are the input values and y are the output values

If x = -2

y = -2+4

y = 2

The coordinate (x, y) will be (-2, 2)

If x = 0

y = 0+4

y = 4

The coordinate (x, y) will be (0,4)

If x = 2

y = 2+4

y = 6

The coordinate (x, y) will be (2, 6)

If x = 6

y = 6+4

y = 10

The coordinate (x, y) will be (6,10)

If x = 8

y = 8+4

y = 12

The coordinate (x, y) will be (8, 12)

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The average number of hours worked per week drop from 2009 to 2010 dropped by 1.16%

The average work weeks are given as:

Year 2009 = 43 hours

Year 2010 = 42 hours 30 minutes

Rewrite as:

Year 2010 = 42.5 hours

The percentage change is then calculated as:

Percentage change= (Final - Initial)/Initial * 100%

So, we have:

Percentage change= (42.5 - 43)/43* 100%

Evaluate

Percentage change= -1.16%

Hence, the average number of hours worked per week drop from 2009 to 2010 dropped by 1.16%

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Answer:

x^4-3x+2

Step-by-step explanation:

There are several different ways to divide algebraic expressions. Here the most simple way to do it (and good idea to try first) is to FACTOR and CANCEL.

see image.

Factor an x from the top. Cancel that x with the bottom x. See image.

(***Also, note: never "cancel" anything connected by a + or a - )

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\frac{x^{5}+(3\times x^{2}) +(2\times x) }{x}} \end{gathered}$}[/tex]

Takes into account expressions that have not yet been taken into account.

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\frac{\red{\not{x}}(x-1)(x^{3}+x^{2} +x-2) }{\red{\not{x}} } } \end{gathered}$}[/tex]

Cancel x in both the  numerator and the denominator.

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{(x-1)(x^{3}+x^{2} +x-2) } \end{gathered}$}[/tex]

The expression expands

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{x^{4}-3x+2 } \end{gathered}$} }[/tex]

From the line bisected with the given midpoints, we have been able to prove that; BC = CE by substitution property of Equality

We are given that;

C is the midpoint of BD

D is the midpoint of CE

1) Thus, BC = CD because of definition of Midpoint.

2) Similarly, by definition of midpoint we know that CD = DE.

3)  We can say that BC = DE because of substitution property of equality.

4) We can say that BC + CD = BD because of segment addition postulate.

5) Similarly, by segment addition postulate, we can say that CD + DE = CE.

6) Finally we can say that BC = CE by substitution property of Equality

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The place value in thousands for the 0 in 10000 is 0 thousands

From the question, we are to the determine the place value in thousands for the 0 in the given number

The given number is

10000

The place value in thousands for the 0 in 10000 is 0 thousands

Hence, the place value in thousands for the 0 in 10000 is 0 thousands

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The data given illustrates that there's a constant ratio of 2 and y = 600(2)^x; 38400

The ratio based on the information given will be:

= 1200/600

= 2

Therefore, the constant ratio is 2.

In 6 years, the population will be:

= 600 × 2^6

= 600 × 64

= 38400

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The measure of angle E in the secant intersection is 21 degrees.

When two secants intersect outside a circle, the circle divides the secants into segments that are proportional with each other

Therefore,

m∠E = 1 / 2 (∠AB - ∠CD)

m∠E = 1 / 2 (80 - 38)

m∠E = 1 / 2 (42)

m∠E = 42 / 2

m∠E = 21 degrees.

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The second option saves time and cleaning elements, so that one is better.

We know that every day you sell a total of 50 bowls, and each one needs 8 oz of onion, this means that you need:

50*8 oz = 400 oz

So you need 400 ounces of onion per day.

If you buy at $1.99 per pound (1 lb = 16 oz)

Then the cost per ounce is:

c = $1.99/16

And the cost of 400 ounces is:

C = ($1.99/16)*400 = $49.75

In the case of the pre-sliced onions, the total cost would be:

C' = ($2.99/16)*400 = $74.75

So in the first case, each portion costs:

$49.75/50 = $0.995

And in the second case:

$74.75/50 =$1.495

So the extra cost is returned by the extra time and savings in cleaning elements, thus, the second option is better.

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Hello,

If we want to factor the expression, we have to solve

3x² + 10x + 8 = 0

a = 3 ; b = 10 ; c = 8

∆ = b² - 4ac = 10² - 4 × 3 × 8 = 4 > 0

x1 = (-b - √∆)/2a = (-10 - 2)/6 = -12/6 = -2

x2 = (-b + √∆)/2a = (-10 + 2)/6 = -8/6 = -4/3

Factor :

a (x - x1)(x - x2)

= 3(x + 2)(x + 4/3)

= (x + 2)(3x + 4)

Answer:

14 and please Mark me brainlist

Answer:

There are four lines of symmetry in this figure.

Step-by-step explanation:

First look at the mainframe, it has 2 lines of symmetry. And if you look at it diagonally, it has another 2 more lines.

So therefore there is 4 lines of symmetry in this H figure.

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If one of the roots is [tex]w=B+2i[/tex], then the other root is its conjugate [tex]\bar w=B-2i[/tex]. So we can factorize the quadratic to

[tex]z^2 + 4z + 20 + iz (A+1) = (z-(B+2i)) (z-(B-2i))[/tex]

Expand the right side and collect all the coefficients.

[tex]z^2 + (4+(A+1)i) z + 20 = z^2 - 2B z + B^2+4[/tex]

From the [tex]z[/tex] and constant terms, we have

[tex]\begin{cases}4 + (A+1)i = -2B \\ 20 = B^2 + 4 \end{cases}[/tex]

From the second equation we get

[tex]B^2 = 16 \implies B = \pm4[/tex]

Then

[tex]4+(A+1)i = \pm8[/tex]

[tex](A+1)i = 4 \text{ or } (A+1)i = -12[/tex]

Since [tex]\frac1i=-i[/tex], we have

[tex]-\dfrac{A+1}i = 4 \text{ or } -\dfrac{A+1}i = -12[/tex]

[tex]A+1 = -4i \text{ or } A+1 = 12i[/tex]

[tex]\boxed{A = -1 - 4i \text{ or } A = -1 + 12i}[/tex]