A hiker walks 11 km due north from camp and then turns and walks 11 km due east.
What is the total distance walked by the hiker?
What is the displacement (on a straight line) of the hiker from the camp?
please answer all questions

Answers

Answer 1
The total distance is gonna be 11+11=22km.

The displacement is gonna be square root of 11^2+11^2 which is 15.556km.

I hope this helps

Related Questions

Determine the Northward and the Eastward components of a 75 m long displacement vector which points in a direction of 27^o E of N.

Answers

Answer:

Eastward = 34.05m

Northward = 66.8m

Explanation:

First, let's define our coordinate axis.

I will choose the North as the positive y-axis and the East as the positive x-axis.

Now we will work with polar coordinates, r and θ and remember that if we want to recover the rectangular coordinates, we need to compute:

x = r*cos(θ)

y = r*sin(θ)

(remember that θ is measured counterclockwise from the positive x-axis)

Now we have:

"... 75 m long displacement vector..."

r = 75m

"...points in a direction of 27° E of N..."

This means that the measure is from the positive y-axis, clockwise (so this is not equivalent to θ).

Now, remember that the angle between the positive y-axis and the positive x-axis is 90°.

Then we will have that θ is the complementary angle to 27°, or:

θ = 90° - 27° = 63°

Now we have θ and r, then we can calculate the rectangular components:

x = 75m*cos(63°) = 34.05m (this is the Eastward component)

y = 75m*sin(63°) = 66.8m (this is the Northward component)

A metal ball sits motionless on a flat surface. Which of these would make the ball move?
A. The force of gravity becomes less.
B. The force of gravity becomes greater.
C. Two equal horizontal opposing forces act upon the ball.
D. Two unequal horizontal opposing forces act upon the ball.

Answers

Answer:

D

Explanation:

Unbalanced forces move stuff. Gravity would only increase/decrease movement if the object was already in motion.

Answer:

b

Explanation:

I WILL MARK YOU AS BRAINLIEST IF RIGHT
What is the magnitude of the net force acting on this object? And what direction?

Answers

Answer:

The magnitude of the net force acting on an object is equal to the mass. and the direction is in 20N

Explanation:

Your TV has a resistance of 10 ohms and a wall voltage of 120 V. How much current and power does it use

Answers

Answer:

Current used is 12 ampere.

Power is 1440 watts.

Explanation:

To find the current used by the TV.

Current (I) = voltage/resistance

Current= 120/10

Current is 12Ampere.

To get power used by the TV,

Power = voltage × current.

= 120× 12

Power = 1440 watts.

Work Done by a Varying Force 06 Work and Energy
w of Energy
100%
2.) The force required to stretch a spring by 1 m from its unstretched length is
150 N. What is the force required to stretch the spring by 3 m?

A. 600 N

B. 450 N

C. 300 N

D. 200 N

Answers

Answer:

B. 450 N

Explanation:

Use Hooke's law:

F = kx

150 N = k (1 m)

k = 150 N/m

F = kx

F = (150 N/m) (3 m)

F = 450 N

A tennis ball is dropped from a roof 16 meters from the ground. How long does it take
for the ball to reach the ground?

Answers

3.3 seconds would be the right answer

The time taken for the tennis ball dropped from the roof-top to reach the ground level is 1.8 seconds.

What is Motion?

Motion is simply the change in position of an object or particle over time.

From the Second Equation of Motion;

s = ut + (1/2)gt²

Where s is the distance from ground level, u is initial velocity, t is time elapsed and g is acceleration due to gravity ( g = 9.8m/s² ).

Given the data in the question;

Since the ball was initially at rest before it was dropped.

Initial velocity u = 0Height or distance from gound level s = 16mTime taken to reach the gound t = ?

We substitute our values into the expression above.

s = ut + (1/2)gt²

16m = ( 0 × t ) + ( (1/2) × 9.8m/s² × t² )

16m = 0.5 × 9.8m/s² × t²

16m = 4.9m/s² × t²

t² = 16m / 4.9m/s²

t² = 3.2653s²

t = √(3.2653s²)

t = 1.8s

Therefore the time taken for the tennis ball dropped from the roof-top to reach the ground level is 1.8 seconds.

Learn more about Equations of Motion here: brainly.com/question/18486505

#SPJ2

7N
6
→ 2N
Net Force:
Determine the net force acting on the object.

Answers

Answer:

When a force is applied to the body, not only is the applied force acting, there are many other forces like gravitational force Fg, frictional force Ff and the normal force that balances the other force. Therefore, the net force formula is given by, FNet = Fa + Fg + Ff + FN.

Explanation:

plzzz helppp
You are pushing a box North in the hallway, at 20n, and a friend gets in front of the box and goes in the opposite direction, at 30n. What direction is the box going at? How much force does the box have going in that direction?​

Answers

Answer:

the box is going south at 10n

Explanation:

2 Why
Force is needed​

Answers

Answer:

A force can cause an object to accelerate, slow down, remain in place, or change shape. The unit of measure for force is the newton which is abbreviated as "N". One newton is the force needed to accelerate one gram of mass by one centimeter per second squared. Other units of force include the dyne and the pound-force.

The epidermis is the top layer of skin compared to the underlying dermis of the
-kin. Using directional terms, where is the epidermis located in relation to the
dermis?
Do
Lateral
Proximal
Superficial
Superior

Answers

Answer:

just as rea was situated at a distance in picture and a half dozen years old in his first comment in picture the actor was the first thing he had ever heard about it he reati was the only person who has

Explanation:

plz help you get the best in your house but muje has been in a relationship since the last

Answer:

Although you may not typically think of the skin as an organ, it is in fact made of tissues that work together as a single structure to perform unique and critical functions. The skin and its accessory structures make up the integumentary system, which provides the body with overall protection. The skin is made of multiple layers of cells and tissues, which are held to underlying structures by connective tissue (Figure 5.1.1). The most superficial layer of the skin is the epidermis which is attached to the deeper dermis. Accessory structures, hair, glands, and nails, are found associated with the skin. The deeper layer of skin is well vascularized (has numerous blood vessels) and is superficial to the hypodermics. It also has numerous sensory, and autonomic and sympathetic nerve fibers ensuring communication to and from the brain.

Explanation:

Describe the layers of the skin and the functions of each layer

-Identify the components of the integumentary system

-Describe the layers of the skin and the functions of each layer

-Describe the layers of the epidermis and dermis

-Identify and describe the hypodermis and fascia

-Describe the role of keratinocytes and their life cycle

-Describe the role of melanocytes in skin pigmentation

A child and sled with a combined mass of 53.9 kg slide down a frictionless slope. If the sled starts from rest and has a speed of 5.71 m/s at the bottom, what is the height of the hill

Answers

Answer:

1.66m

Explanation:

Using the conservation law

PE = KE

mgh = 1/2mv²

gh = V²/2

g is the acceleration due to gravity = 9.81m/s²

h is the height of the hill

V is the velocity = 5.71m/s

Substitute

9.81h = 5.71²/2

Cross multiply

2×9.81h = 5.71²

19.62h = 32.6041

h = 32.6041/19.62

h = 1.66m

Hence the height of the hill is 1.66m

A boat initially moving at 10 m/s accelerates at 2 m/s for 10 s. What is the velocity of the boat after 10 seconds?

Answers

Answer:

30 m/s

Explanation:

v = u + at

given that,

u = 10 m/s (initial speed)a = 2 m/s^2 t = 10sv =?(final speed)

v = 10 + ( 2 × 10)

v = 10 + 20

v = 30 m/s

An airplane accelerates down a runway at 4.3 m/s2​ ​ for 48 s until it finally lifts off the ground. Determine the distance traveled before takeoff.

I

Answers

Answer:

x=4953.6m

Explanation:

used formula x=xo+vot+1/2at^2

A charged isolated metal sphere of diameter 12 cm has a potential of 9200 V relative to V = 0 at infinity. Calculate the energy density in the electric field near the surface of the sphere.

Answers

Answer:

0.1 J/m³

Explanation:

We know that

V = k Q / R

We also know that

E = k Q / R²

Joining the two equations together, we have

E = V / R

To solve the question proper, we'd be using the formula

u = 1/2 E• E², substitute for E, we have

u = 1/2 E• (V/R)²

u = 1/2 * 8.85*10^-12 * (9000 / 0.06)²

u = 1/2 * 8.85*10^-12 * 150000²

u = 1/2 * 8.85*10^-12 * 2.25*10^10

u = 1/2 * 0.199125

u = 0.0996

u = 0.1 J/m³

The energy density is 0.1 J/m³

As the ball falls, how will the kinetic energy change? How will the gravitational potential energy change? How will the mechanical energy change?

Answers

Answer:

the Kinetic energy of the ball also increases.

the potential energy of the ball also increases.

mechanical energy of ball remains same.

Explanation:

KINETIC ENERGY:

The kinetic energy of the object depends upon the velocity of the object. As the formula suggests:

K.E = (1/2)mv²

As, the ball is falling down, it accelerates with a value equal to acceleration due to gravity. Thus, the speed increases as the ball falls.

Therefore, the Kinetic energy of the ball also increases.

POTENTIAL ENERGY:

Th potential energy of an object depends upon its height. As, the formula suggests:

P.E = mgh

As, the ball falls, its height decreases.

Therefore, the potential energy of the ball also increases.

MECHANICAL ENERGY:

Mechanical energy is the sum of kinetic energy and potential energy. According to law of conservation of energy, the total energy of the system always remains constant. It may change the forms but the total energy remains same. Thus, in this case potential energy is converted to kinetic energy.

Therefore, mechanical energy of ball remains same.

21. A toy car starts from rest and begins to accelerate at 11.0 m/s2. What is the toy
car's final velocity after 6.0 seconds?

Answers

Answer:

Explanation:

Given parameters:

Initial velocity = 0

Acceleration = 11m/s²

Time  = 6s

Unknown:

Final velocity  = ?

Solution:

 From the given parameters, we use one of the appropriate equations of motion to solve this problem.

     V = U + at

V is the final velocity

U is the initial velocity

a is the acceleration due to gravity

t is the time taken

Input the parameters and solve;

     V  = 0 + 11 x6

     V  = 66m/s

The final velocity is 66m/s

Can someone please help me with this following question, If you could visit Pangaea what animals would you find
A). Penguins
B). Mammals
C). Dinosaurs
D). Eagles

Answers

Answer:

C). Dinosaurs

Explanation:

An empty 50-g bowl rests on a scale that measures force (in newtons). Water is then poured into the scale from a height of 0.50 m and rate of 10 mL/s. Assuming that the water does not splash as it comes to rest, calculate the reading on the scale at t = 5.0 s

Answers

Answer:

1 Newton

Explanation:

Mass of bowl (Mb) = 50 g = 0.05 kg

Initial Velocity (Vo) = 10 mL/s = 10g/s

time (t) = 5.0s

Mass of water (Mw) = 10 g/s * 5s = 50 g = 0.05 kg

*Vob = initial velocity of bowl

*Vow = initial velocity of water

*Vf = final velocity

*g = gravity = 9.8

Conservation of momentum [Inelastic Collision]:

(m1)(Vo1) + (m2)(Vo2) = (M1+M2)Vf(Mw)(Vow) +  (Mb)(Vob) = (Mw+Mb)Vf(50g)(10g/s) + (50g)(0) = (50g + 50g)(Vf)Vf = 500/100 = 5g/s = 0.005kg/s

Impulse-Momentum Theorem:

Δp = mΔv

Scale Reading:

Δp + Mw(g) + Mb(g)= (0.05kg + 0.05kg)*(0.05kg/s) + (0.05kg*9.8) +(0.05kg*9.8)= 0.9805 = 1 Newton

Man A (70kg) and Man B (90kg) are hanging motionless from a platform at rest. What is the tension TA in the top rope if the platform accelerates upward at a constant rate of 2 m/s2

Answers

Answer:

The tension in the upper rope (top rope), T1 = 1,888 N

Explanation:

The Parameters that were given:

Mass A, M1 = 70kg

Mass B. M2 = 90kg

acceleration, a = 2 m/s2

Assume the rope doesn't have mass, acceleration due to gravity, g

= 9.8 m/s2

The tension, T in a platform = m (a + g)

Then the tension, T1 in the upper rope = m1 (a + g) + T2

Where T2 = Tension in the lower rope

First, we calculate T2

Since the platform accelerates upward the acceleration would be positive

T2 =  m2 (a + g)

T2 = 90kg ( 2 m/s2 + 9.8 m/s2)

T2 = 1,062N

To calculate the tension T1,

T1 = m1 (a + g) + T2

= 70kg (2 m/s2 + 9.8 m/s2) + 1062N

T1 = 1,888 N

1. Which statement is true of culture?
O Culture do not change or evolve
O Culture refers to the degree in which resources are used to address for problems.
O Culture has little affect on a persons life
Food can reflect culture

Answers

I think it is either A or B. I’m mostly leaning towards B.

Consider a particle of mass m which can move freely along the x axis from -a/2 to a/2, but which is strictly prohibited from being found outside this region. The wave function of the particle within the allowed region is

Answers

Answer:

  φ = B sin (2π n/a   x)

Explanation:

In quantum mechanics when a particle moves freely it implies that the potential is zero (V = 0), so its wave function is

     φ = A cos kx + B sin kx

we must place the boundary conditions to determine the value of the constants A and B.

In our case we are told that the particle cannot be outside the boundary given by x = ± a / 2

therefore we must make the cosine part zero, for this the constant A = 0, the wave function remains

    φ = B sin kx

the wave vector is

      k = 2π /λ

now let's adjust the period, in the border fi = 0 therefore the sine function must be zero

         φ (a /2) = 0

          0 = A sin (2π/λ  a/2)

therefore the sine argument is

          2π /λ   a/2 = n π

          λ= a / n

we substitute

          φ = B sin (2π n/a   x)

which two types of information are found in an elements box in the periodic table

Answers

Answer:

Each box represents an element and contains its atomic number, symbol, average atomic mass, and (sometimes) name.

Explanation:

Answer:

An element's period and group



A football team lost 3 yards on their first play. On the second play, 10 yards were gained. On the third play the quarterback got tackled behind the line of scrimmage and lost 6 yards. What was their net gain or loss after the three plays?​

Answers

+1yd

Explanation:

Kfgjjh

Answer:

+1 YD

Explanation:

-3 + 10 - 6 = 1

Help plz!:( it’s for physics but it has like math !!
(SHOW ALL WORK)

1) A 30-kg object is accelerated at a rate of 3m/s2. how much force does the object have?

2)A ball is thrown w/ a force of 50N and travels 4m. how much work is done to the ball?

3) Joey pushes on a door that is stuck with 400 N of force but is unable to move it. How much work has he done?

4) A toy car does 300j of work in 15 sec. how much power did the car use?

5)A 60w light bulb burns for 2 min. how much work was done?

6) how much power is used if it takes Frank (a 450 N boy) 3 sec to run 2 meters?

Answers

Answer:

1. 90N

2. 200N

3. 400N

4.20w

5.7200N

Explanation:

1.F=ma

30 * 3 = 90

2.W=FD

50 * 4=200

4. P=W/t

300/15=20

5.W= Pt. 2minutes = 120sec

60*120 = 7200

A 30.0-kgkg box is being pulled across a carpeted floor by a horizontal force of 230 NN , against a friction force of 210 NN . What is the acceleration of the box?

Answers

Answer:

The acceleration of the box is 0.67 m/s²

Explanation:

Given that,

Mass of box = 30.0 kg

Horizontal force = 230 N

Friction force = 210 N

We need to calculate the acceleration of the box

Using balance equation

[tex]F-f_{k}=ma[/tex]

[tex]a=\dfrac{F-f_{k}}{m}[/tex]

Where, F = horizontal force

[tex]f_{k}[/tex] =frictional force

m= mass of box

a = acceleration

Put the value into the formula

[tex]a=\dfrac{230-210}{30}[/tex]

[tex]a=0.67\ m/s^2[/tex]

Hence, The acceleration of the box is 0.67 m/s²

A pendulum can be formed by tying a small object, like a tennis ball, to a string, and then connecting the other end of the string to the ceiling. Suppose the pendulum is pulled to one side and released at t1. At t^2, the pendulum has swung halfway back to a vertical position. At t^3, the pendulum has swung all the way back to a vertical position. Rank the three instants in time by the magnitude of the centripetal acceleration, from greatest to least. Most of the homework activities will be Context-rich Problems.

Answers

Answer:

1- t^3

2- t^2

3- t1

Explanation:

The acceleration produced in a body, while travelling in a circular motion, due to change in direction of motion is called centripetal acceleration. The formula of the centripetal acceleration is as follows:

ac = v²/r

where,

ac = centripetal acceleration

v = speed

r = radius

for a constant radius the centripetal acceleration will be directly proportional to the speed of object. The speed of pendulum will be lowest at t1 due to zero speed initially. Then the speed will increase gradually having greater speed at t^2 and the highest speed and centripetal acceleration at t^3. Therefore, the three instants in tie can be written in following order from greatest centripetal acceleration to lowest:

1- t^3

2- t^2

3- t1

the equation of motion is given for a particle when s is in meters and t is in seconds. Find the acceleration after 4.5 seconds s

Answers

Answer:

Explanation:

The question is incomplete.

The equation of motion is given for a particle, where s is in meters and t is in seconds. Find the acceleration after 4.5 seconds.

s= sin2(pi)t

Acceleration = d²S/dt²

dS/dt = 2πcos2πt

d²S/dt² = -4π²sin2πt

A(t) = -4π²sin2πt

Next is to find acceleration after 4.5 seconds

A(4.5) = -4π²sin2π(4.5)

A(4.5) = -4π²sin9π

A(4.5) = -4π²sin1620

A(4.5) = -4π²(0)

A(4.5) = 0m/s²

g (a) Calculate the block's final speed when it reaches the bottom of the frictionless inline. Keep 2 decimal places.

Answers

Answer:

Explanation:

The question is incomplete. Here is the complete question with attachment below.

In the above figure on the LEFT side, a block (mass = 2.8 kg) starts from rest at the top of a frictionless inline and slides to the bottom. The height of the incline is h=6.5 m, angle

A uniform magnetic field of magnitude 0.72 T is directed perpendicular to the plane of a rectangular loop having dimensions 8.2 cm by 14 cm. Find the magnetic flux through the loop.

Answers

Answer:

Explanation:

Magnetic flux is expressed as the product of magnetic field and cross sectional area.

Φ = BAsintheta

Given

B = 0.72T

A = 8.2cm×14cm

A = 0.082m × 0.14m

Area = 0.01148m²

Theta = 90°

Substitute into the formula

Φ = BAsintheta

Φ = 0.72(0.01148)sin90°

Φ = 0.72(0.01148)(1)

Φ = 0.0082656

Hence the magnetic flux through the loop is 8.2656 × 10^-3 Weber

Pleeeease Help!!
How did the parallel circuit respond differently to these changes than a series circuit?
Adding Bulbs: __________
Removing Bulbs: ________

Answers

Answer:

adding bulbs:bulbs will glow in parallel circuit.

but the brightness of each bulb differs in series circuit.

removing bulbs:if u remove a bulb from parallel circuit,the other bulbs continue glowing in the same brightness

but if u remove a bulb in series circuit,the brightness of each bulb increases.

Answer:

The person above is correct.

Explanation:

In a parallel sequence, the light bulbs have electrons that flow equally. Though, in a series circuit, it's mainly connected to one wire, and the electrons get weaker.

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