Un estudiante preparo 200 ml de solución de acetato de potasio (CH3COOH ; Masa molar = 98 g/mol ; Ka CH3COOH = 1,8 x 10-5), disolviendo 3,5 g de ácido, la que denomino "Solución A". Posteriormente preparo otra solución de menor concentración del mismo soluto que denomino "solución B" y para ello tomo un volumen de 5,5 ml de la solución A y agrego agua hasta 70 ml de solución. Señale el pH de solución A y B y, la concentración molar de CH3COO- en la solución b.

Answers

Answer 1

Answer:

mirar respuesta abajo

Explanation:

Muy bien. Antes de responder lo que piden en el problema, vamos a calcular la concentración inicial de la solución A:

1) Concentración de la solución A:

En este caso, se sabe que se usaron 3,5 g de la sal, se puede calcular los moles usando el peso molecular y la masa:

n = m/PM  (1)

Aplicando tenemos:

n = 3,5 / 98 = 0,0357 moles

Conociendo los moles, podemos calcular la concentración:

M = n/V (2)

Aplicando la formula tenemos:

M = 0.0357 / 0.200 = 0.1785 M

Esta es la concentración del ácido etiquetado como "Solución A".

Ahora podemos ver la concentración de la solución B, para luego calcular las concentraciones molares de los iones en solución y sus respectivos pH.

2) Concentración del ácido en la solución B:

Con la concentración de "A", se puede determinar la concentración de la solución B. Aqui podemos esperar que sea un valor mas bajo, puesto que es una dilución la que estamos haciendo. Por lo tanto.

Si se toma 5.5 mL de la solución A, entonces:

n = 0.1785 * 0.0055 = 0.00098 moles

Con esto, se calcula la nueva concentración:

M = 0.00098 / 0.070 = 0.014 M

Esta es la concentración de la solución B. Ahora para calcular pH y concentraciones de los iones en equilibrio, hay que plantear la reacción acido base en equilibrio. Como es el mismo compuesto, usaremos la misma ecuación.

3) pH de las soluciones A y B:

Planteamos la reacción de equilibrio:

CH₃COO⁻ + H₂O <------> CH₃COOH + OH⁻     Kb

Calculando el Kb, sería asi:

Kb = Kw/Ka

Kb = 1x10⁻¹⁴ / 1.8x10⁻⁵ = 5.56x10⁻¹⁰

Ahora reescribimos la ecuación y hacemos una tabla de equilibrio:

       CH₃COO⁻ + H₂O <------> CH₃COOH + OH⁻     Kb = 5.56x10⁻¹⁰

i)        0.1785                                    x              x

eq)    0.1785-x                                  x              x

Kb = [OH⁻] [CH₃COOH] / [CH₃COO⁻]

Reemplazando nos queda:

5.56 * 10⁻¹⁰ = x² / (0.1785-x)      

Y como Kb es muy pequeño, se asume que el valor de x será también pequeño, asi que podemos redondear la resta a simplemente 0.1785, quedando tan solo:

5.56 * 10⁻¹⁰ = x² / (0.1785)

x² = 5.56*10⁻¹⁰ * 0.1785

x = √9.9246*10⁻¹¹

x = 9.96*10⁻⁶ M

Esta es la concentración de [OH⁻] y [CH₃COO⁻] en la solución A.

Aplicando lo mismo para la solución B (Cambiando solo el dato de concentración) nos queda:

x = √5.56*10⁻¹⁰ * 0.014

x = 2.79x10⁻⁶ M = [OH⁻] = [CH₃COO⁻]

Finalmente, para calcular pH, se calcula primero el pOH y luego el pH:

pH = 14 - pOH

pOH = -log[OH⁻]

Para la solución A:

pOH = -log(9.96*10⁻⁶) = 5

pH = 14 - 5

pH = 9

En el caso de la solución B:

pOH = -log(2.79*10⁻⁶) = 5.55

pH = 14 - 5.55

pH = 8.45

Espero te ayude


Related Questions

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2 – 7 – 7
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The relations of the quantum numbers allow to find that the correct answer for the configuration of the excited state is:

  2 - 7 - 7

The electronic configuration of the elements is the distribution of electrons and different levels and sublevels fulfilling the relationships between quantum numbers.  

The principal quantum number (n) goes from 0 to infinity The orbital quantum number (l) goes from 0 to n-1, in general it is represented by lera s, p, d, f The magnetic quantum number ([tex]m_l[/tex]) ranges from -l to l The spin quantum number ([tex]m_s[/tex]) can have two values ​​+ ½ and - ½

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This is at the lowest energy configuration, when the atom acquires energy, an electron from its shell must be promoted to the next level.

                       

That is, an electron from level n = 2 that is full is promoted to level n = 3 since in this shell there is still room for two electrons, the configuration of the excited state is:

                  2- 7 - 7

Let's examine the different alternatives:

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False, this is the configuration of the base state

2) 2 - 7 - 7

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False, in this configuration the atom becomes an ion

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In conclusion using the relationships of quantum numbers we can find that the correct answer for the excited state configuration is:

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Answers

Answer:

The statement that is true is:

II. Scientific explanations should be based on evidence or data.

                                                                                     ~Lylliara Jackson~

1 pc
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Answers

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Explanation:

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Answer:

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cell wall only present in plant cell and prokaryotic cell while it is absent in animal cell, the function of cell wall is to provide protection

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Answers

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C.

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Edg. 2020

Other guy is right i got 100%

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Answers

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Answers

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The charge-to-mass ratio of electrons is always the same constant, no matter which substances are used in the cathode ray tube.

Explanation:

Thomson in his model of atom discussed that the atom consists of a negative charge particle termed electron randomly distributed in the positively charged sphere to balance the negative charge.His model of the atom was also known as the Plum pudding model of the atom. In which electrons are embedded in positive soup.He discovered electrons by conducting an experiment with cathode rays in which cathode rays emerging from the cathode were observed to be deflected towards the positively charged plate.He also conducted the same experiment with different metals (for anode and cathode) and gases and found out that the charge to mass ratio of the electron was regardless of the metals or gases used in the experiment.With this, he landed on the conclusion that these particles of cathode rays are the universal component of matter.

So, from this, we can conclude that the charge-to-mass ratio of electrons is always the same constant, no matter which substances are used in the cathode ray tube describes Thomson's conclusion that electrons are present in all atoms.

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Answers

5 units to the left.

Explanation:
They are working against each other. That means you subtract.

32 - 37 = -5

You are moving 5 units to the left because 37 is negative which means it is moving left. The key word is left. In physics, you would get the same answer if you did it this way.

37 - 32 = 5

The 5 moves in the same direction as the 37

Water can undergo a change of state when its energy changes at specific temperatures. Solid water, or ice, changes into liquid water when its energy increases at its melting point. a. Describe this process. b. Explain how the energy changes with each state.

Answers

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Explanation:

a. The process of a solid turning into liquid is called melting. The solid ice turns into a liquid during the melting process. The solid molecules gain energy and flow as a liquid.

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Answers

Answer:They indicate the number of molecules of each substance

Explanation:

When we write chemical reaction equations, we usually put a number before the symbol of each reactant.

These coefficient shows the number of molecules of that specie that is involved in the balanced reaction equation for the reaction.

These coefficients are important because they are used in carrying out stoichiometric calculations.

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Answers

Answer:first one

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A pure substance has same chemical properties throughout , it cannot be  separated by any means and it is made up of one kind of atom.

What are chemical properties?

These properties are defined as those properties which become evident during or after a chemical reaction after the identity of the substance is changed during chemical reaction.

These properties cannot be determined externally just by viewing the substance ,these change immensely after a substance undergoes a chemical change.These are used for identification of unknown substances and for building up chemical classifications.

The major chemical properties are flammability,toxicity,reactivity,acidity and heat of combustion.For a chemical property to be apparent , it is necessary that the structure of the substance is altered.

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